初等数学I · free preview

多项式方程

一元二次方程的求根公式、判别式与韦达定理;双二次方程与换元法。

1. Introduction: From Linear to Quadratic

Introduction: From Linear to Quadratic

2. Discriminant and Root Formula

Discriminant and Root Formula

3. Discriminant Cases

When Δ=0\Delta=0, how many real roots does the quadratic equation ax2+bx+c=0ax^2+bx+c=0 have?

4. Vieta's Theorem: Roots and Coefficients

Vieta's Theorem: Roots and Coefficients

5. Computing Sum and Product with Vieta's Theorem

What is the product PP of the roots of 2x2+3x−5=02x^2+3x-5=0?

6. Deriving the Root Formula by Completing the Square

Deriving the Root Formula by Completing the Square

7. Discriminant After Completing the Square

After completing the square we get (x+b2a)2=Δ4a2\left(x+\dfrac{b}{2a}\right)^2=\dfrac{\Delta}{4a^2}. What condition is required to take the square root?

8. Factorization Using the Roots

Factorization Using the Roots

9. Factorization Result

When 3x2+7x+23x^2+7x+2 is factored in the form a(x−α)(x−β)a(x-\alpha)(x-\beta), what is aa?

10. Substitution for Biquadratic Equations

Substitution for Biquadratic Equations

11. Biquadratic Substitution

What substitution reduces the biquadratic equation ax4+bx2+c=0ax^4+bx^2+c=0 to a quadratic equation?

12. Worked Example: Discriminant and Double Root

Worked Example: Discriminant and Double Root

13. Exercise: Solving a Quadratic Equation

Find the two roots of x2−5x+6=0x^2-5x+6=0, separated by semicolons from smallest to largest.

14. Exercise: Symmetric Expressions with Vieta's Theorem

Let α\alpha and β\beta be the roots of 2x2−x−3=02x^2-x-3=0. Use Vieta's theorem to find α2+β2\alpha^2+\beta^2. Enter a number (as a fraction such as p/q).

15. Exercise: Biquadratic Equation

Solve the biquadratic equation x4−5x2+4=0x^4-5x^2+4=0. List all real roots, separated by semicolons from smallest to largest.

16. Flashcard: Three Cases of the Discriminant

How does the sign of Δ\Delta determine the number of real roots of the quadratic equation ax2+bx+c=0ax^2+bx+c=0?

17. Self-Explain: Discriminant and Roots

Explain in your own words: why do we say 'one double root' when Δ=0\Delta=0 but 'two distinct real roots' when Δ>0\Delta>0? When Δ<0\Delta<0 the equation has no roots over the reals; how is this conclusion seen from the process of completing the square?

18. Comprehensive Check

Comprehensive Check

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