Calculus Prelude · free preview

5.3 Modeling with polynomial functions (continued)

Why do polynomials arise naturally in the study of problems involving the volume and surface area of three-dimensional containers such as boxes and cylinders?

1. Summary

Summary

2. An open triangular trough

An open triangular trough, as pictured in Figure is being constructed from aluminum. The trough is to have equilateral triangular ends of side length ss and a length of ll. We want the trough to used a fixed 100100 square feet of aluminum.

  • What is the area of one of the equilateral triangle ends as a function of ss? - Recall that for an object with constant cross-sectional area, its volume is the area of one of those cross-sections times its height (or length). Hence determine a formula for the volume of the trough that depends on ss and ll. - Find a formula involving ss and ll for the surface area of the trough. - Use the constraint that we have 100100 square feet of available aluminum to generate an equation that connects ss and ll and hence solve for ll in terms of ss. - Use your work in (d) and (b) to express the volume of the trough, VV, as a function of ss only. - What is the domain of the function VV in the context of the situation being modeled? Why?

3. A rectangular box is…

A rectangular box is being constructed so that its base is twice as long as it is wide. In addition, the base and top of the box cost $22 per square foot while the sides cost $1.501.50 per square foot. If we only want to spend $1010 on materials for the box, how can we write the box's volume as a function of a single variable? What is the domain of this volume function? (Hint: first find the box's surface area in terms of two variables, and then find an expression for the cost of the box in terms of those same variables. Use the fact that cost is constrained to solve for one variable in terms of another.)

4. Suppose that we want…

Suppose that we want a cylindrical barrel to hold 88 cubic feet of volume. Let the barrel have radius rr and height hh, each measured in feet. How can we write the surface area, AA, of the barrel solely as a function of rr?

  • Draw several possible pictures of how the barrel might look. For instance, what if the radius is very small? How will the height appear in comparison? Likewise, what happens if the height is very small? - Use the fact that volume is fixed at 88 cubic feet to state a constraint equation and solve that equation for hh in terms of rr. - Recall that the surface area of a cylinder is A=2πr2+2πrhA = 2\pi r^2 + 2\pi rh. Use your work in (c) to write AA as a function of only rr. - What is the domain of AA? Why? - Explain why AA is not a polynomial function of rr.

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