微积分I(标准路径) · free preview

§2.1 Elementary derivative rules (continued)

导数有哪些其他记号?

1. Summary

Summary

2. Let $f$ and $g$ be d…

Let ff and gg be differentiable functions for which the following information is known: f(2)=5f(2) = 5, g(2)=−3g(2) = -3, f′(2)=−1/2f'(2) = -1/2, g′(2)=2g'(2) = 2. - Let hh be the new function defined by the rule h(x)=3f(x)−4g(x)h(x) = 3f(x) - 4g(x). Determine h(2)h(2) and h′(2)h'(2). - Find an equation for the tangent line to y=h(x)y = h(x) at the point (2,h(2))(2,h(2)). - Let pp be the function defined by the rule p(x)=−2f(x)+12g(x)p(x) = -2f(x) + \frac{1}{2}g(x). Is pp increasing, decreasing, or neither at a=2a = 2? Why? - Estimate the value of p(2.03)p(2.03) by using the local linearization of pp at the point (2,p(2))(2,p(2)).

3. Let functions $p$ an…

Let functions pp and qq be the piecewise linear functions given by their respective graphs in Figure 2.1. Use the graphs to answer the following questions.

  • At what values of xx is pp not differentiable? At what values of xx is qq not differentiable? Why? - Let r(x)=p(x)+2q(x)r(x) = p(x) + 2q(x). At what values of xx is rr not differentiable? Why? - Determine r′(−2)r'(-2) and r′(0)r'(0). - Find an equation for the tangent line to y=r(x)y = r(x) at the point (2,r(2))(2,r(2)).

4. Consider the functio…

Consider the functions r(t)=ttr(t) = t^t and s(t)=arccos⁡(t)s(t) = \arccos(t), for which you are given the facts that r′(t)=tt(ln⁡(t)+1)r'(t) = t^t(\ln(t) + 1) and s′(t)=−11−t2s'(t) = -\frac{1}{\sqrt{1-t^2}}. Do not be concerned with where these derivative formulas come from. We restrict our interest in both functions to the domain 0<t<10 \lt t \lt 1. - Let w(t)=3tt−2arccos⁡(t)w(t) = 3t^t - 2\arccos(t). Determine w′(t)w'(t). - Find an equation for the tangent line to y=w(t)y = w(t) at the point (12,w(12))(\frac{1}{2}, w(\frac{1}{2})). - Let v(t)=tt+arccos⁡(t)v(t) = t^t + \arccos(t). Is vv increasing or decreasing at the instant t=12t = \frac{1}{2}? Why?

5. Let $f(x) = a^x$. Th…

Let f(x)=axf(x) = a^x. The goal of this problem is to explore how the value of aa affects the derivative of f(x)f(x), without assuming we know the rule for ddx[ax]\frac{d}{dx}[a^x] that we have stated and used in earlier work in this section. - Use the limit definition of the derivative to show that

f′(x)=lim⁡h→0ax⋅ah−axhf'(x) = \lim_{h \to 0} \frac{a^x \cdot a^h - a^x}{h}

. - Explain why it is also true that

f′(x)=ax⋅lim⁡h→0ah−1hf'(x) = a^x \cdot \lim_{h \to 0} \frac{a^h - 1}{h}

. - Use computing technology and small values of hh to estimate the value of

L=lim⁡h→0ah−1hL = \lim_{h \to 0} \frac{a^h - 1}{h}

when a=2a = 2. Do likewise when a=3a = 3. - Note that it would be ideal if the value of the limit LL was 11, for then ff would be a particularly special function: its derivative would be simply axa^x, which would mean that its derivative is itself. By experimenting with different values of aa between 22 and 33, try to find a value for aa for which

L=lim⁡h→0ah−1h=1L = \lim_{h \to 0} \frac{a^h - 1}{h} = 1

. - Compute ln⁡(2)\ln(2) and ln⁡(3)\ln(3). What does your work in (b) and (c) suggest is true about ddx[2x]\frac{d}{dx}[2^x] and ddx[3x]\frac{d}{dx}[3^x]? - How do your investigations in (d) lead to a particularly important fact about the function f(x)=exf(x) = e^x?

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