微积分I(标准路径) · free preview

§1.7 Limits, continuity, and differentiability (continued)

从图象上看,说当 $x \to a$ 时 $f$ 有极限 $L$ 是什么意思?这与 $f$ 在 $x = a$ 处有左极限和右极限有什么联系?

1. Summary

Summary

2. Consider the graph o…

Consider the graph of the function y=p(x)y = p(x) that is provided in Figure 1.7. Assume that each portion of the graph of pp is a straight line, as pictured.

  • State all values of aa for which lim⁡x→ap(x)\lim_{x \to a} p(x) does not exist. - State all values of aa for which pp is not continuous at aa. - State all values of aa for which pp is not differentiable at x=ax = a. - On the axes provided in Figure 1.7, sketch an accurate graph of y=p′(x)y = p'(x).

3. For each of the foll…

For each of the following prompts, give an example of a function that satisfies the stated criteria. A formula or a graph, with reasoning, is sufficient for each. If no such example is possible, explain why. - A function ff that is continuous at a=2a = 2 but not differentiable at a=2a = 2. - A function gg that is differentiable at a=3a = 3 but does not have a limit at a=3a=3. - A function hh that has a limit at a=−2a = -2, is defined at a=−2a = -2, but is not continuous at a=−2a = -2. - A function pp that satisfies all of the following: -p(−1)=3p(-1) = 3 and lim⁡x→−1p(x)=2\lim_{x \to -1} p(x) = 2-p(0)=1p(0) = 1 and p′(0)=0p'(0) = 0-lim⁡x→1p(x)=p(1)\lim_{x \to 1} p(x) = p(1) and p′(1)p'(1) does not exist

4. Let $h(x)$ be a func…

Let h(x)h(x) be a function whose derivative y=h′(x)y= h'(x) is given by the graph on the right in Figure 1.7. - Based on the graph of y=h′(x)y = h'(x), what can you say about the behavior of the function y=h(x)y = h(x)? - At which values of xx is y=h′(x)y = h'(x) not defined? What behavior does this lead you to expect to see in the graph of y=h(x)y=h(x)? - Is it possible for y=h(x)y = h(x) to have points where hh is not continuous? Explain your answer. - On the axes provided at left, sketch at least two distinct graphs that are possible functions y=h(x)y = h(x) that each have a derivative y=h′(x)y = h'(x) that matches the provided graph at right. Explain why there are multiple possibilities for y=h(x)y = h(x).

5. Consider the functio…

Consider the function g(x)=∣x∣g(x) = \sqrt{|x|}. - Use a graph to explain visually why gg is not differentiable at x=0x = 0. - Use the limit definition of the derivative to show that

g′(0)=lim⁡h→0∣h∣hg'(0) = \lim_{h \to 0} \frac{\sqrt{|h|}}{h}

. - Investigate the value of g′(0)g'(0) by estimating the limit in (b) using small positive and negative values of hh. For instance, you might compute ∣−0.01∣0.01\frac{\sqrt{|-0.01|}}{0.01}. Be sure to use several different values of hh (both positive and negative), including ones closer to 0 than 0.01. What do your results tell you about g′(0)g'(0)? - Use your graph in (a) to sketch an approximate graph of y=g′(x)y = g'(x).

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